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Is e^x=ln(x) solvable?

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We will solve an interesting algebraic equation involving both exponential and logarithm, namely e^x=ln(x). Although the graphs of y=e^x and y=ln(x) do not intercept, we can actually find some complex solutions to this equation. We do need to use the Lambert W function tho. So see here for a detailed lecture. Lambert W function Lecture: https://youtu.be/Qb7JITsbyKs We will make b^x and log_b(x) tangent to each other here: https://youtu.be/uMfOsKWryS4 Check out Mu Prime Math's video on when is f(x)=f^-1(x)=x true: https://youtu.be/53lBKCBrENY šŸ’Ŗ Support this channel, https://www.patreon.com/blackpenredpen šŸ› Euler's Identity e^(iĻ€)+1=0 t-shirt: https://amzn.to/427Seae Subscribe for more math for fun videos šŸ‘‰ @blackpenredpen

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