あい ai 【韓国在住コスメオタク】
@airoom111 • Joined April 24, 2018
At a glance
あい ai 【韓国在住コスメオタク】 ranks #2,447,176 globally for subscribers (2.02K), #2,806,702 globally for views (223K), 49 videos published from JP.
Subscribers
2,023
Views
223,722
Videos
49
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
4.56K
Total views ÷ total videos
Views per subscriber
111×
Total views ÷ subscribers
Subs per video
41
Subscribers ÷ total videos
Analytics tables
About
皆さんこんにちは！あいです💜 韓国で会社員をしながら趣味のコスメオタクを共有したくてYouTubeしてますㅎㅎ 韓国のコスメ事情やたまに韓国🇰🇷のvlogなどもアップロードしていくので沢山遊びにきて頂ければ嬉しいです！ また韓国のこういう所知りたい！こんな動画が見たい！等あればコメントで教えて下さると嬉しいです🥺🫶
- Handle
- @airoom111
- Joined
- April 24, 2018
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.