At a glance
지식한스푼 ranks #376,283 globally for subscribers (143K), #224,136 globally for views (93.1M), 1.17K videos published from KR.
Subscribers
143,105
Views
93,190,113
Videos
1,176
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
79.2K
Total views ÷ total videos
Views per subscriber
651×
Total views ÷ subscribers
Subs per video
122
Subscribers ÷ total videos
Analytics tables
About
국내외 경제·외교·국방·산업 정보를 흥미롭게 전합니다. 공개된 기사, 방송, 유튜브, 논문, 위키백과 등을 토대로 세계의 역사, 시사정보 등을 통해 교육가치를 제공합니다. 문의 [email protected] Thank you always. Have a good today. from 위튜브 MR.TTOLP Contents Design
- Handle
- @mrttolp
- Joined
- September 1, 2017
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.