At a glance
愛爾達綜合台 ranks #272,577 globally for subscribers (223K), #222,914 globally for views (95.0M), 10.0K videos published from TW.
Subscribers
223,232
Views
95,048,418
Videos
10,056
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
9.45K
Total views ÷ total videos
Views per subscriber
426×
Total views ÷ subscribers
Subs per video
22
Subscribers ÷ total videos
Analytics tables
About
「愛爾達綜合台」是目前全台最強的HD高畫質綜合頻道。 頻道內容包羅萬象、節目精采可期,我們有強檔日本偶像劇、當紅黃金大陸劇、超人氣動畫卡通、自製的旅遊知性及自然人文節目,適合全家大小一起觀賞。更多精彩節目內容,敬請鎖定愛爾達綜合台CH300(中華電信MOD)。更多節目資訊請上,愛爾達綜合台官方粉絲團:https://www.facebook.com/ELTAWORLD
- Handle
- @eltaworld
- Joined
- November 9, 2012
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.