象棋特大王天一
@xiangqiwangtianyi • Joined December 27, 2018
At a glance
象棋特大王天一 ranks #1,062,602 globally for subscribers (22.6K), #377,106 globally for views (41.1M), 5.73K videos published from HK.
Subscribers
22,652
Views
41,114,145
Videos
5,733
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
7.17K
Total views ÷ total videos
Views per subscriber
1,815×
Total views ÷ subscribers
Subs per video
4
Subscribers ÷ total videos
Analytics tables
About
象棋特级大师王天一，虎牙直播签约主播。 与海外棋友一起感受象棋的无穷奥妙！ 虎牙直播搜索：王天一可观看直播内容。 频道邀请多位象棋大师讲解王天一大师的精彩棋局。 王天一：中国象棋特级大师，自2014年起始终排名中国象棋职业棋手等级分第一。
- Handle
- @xiangqiwangtianyi
- Joined
- December 27, 2018
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.