At a glance
電玩醫生 馬克羊 ranks #927,686 globally for subscribers (30.9K), #1,632,744 globally for views (1.60M), 164 videos published from TW.
Subscribers
30,931
Views
1,609,731
Videos
164
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
9.81K
Total views ÷ total videos
Views per subscriber
52×
Total views ÷ subscribers
Subs per video
189
Subscribers ÷ total videos
Analytics tables
About
楊震醫師,職業當沖交易者 科學奧林匹亞金牌/世界冠軍 群益期貨投顧部講師 專精各種遊戲,股票期貨、考試、爐石 用數學和心理學遊戲人間 期貨交易具有一定風險,交易人應先評估本身資金及所能負擔之風險,過去績效或未來預期的表現不可作為日後績效之保證。 群益期貨股份有限公司 114年金管期總字第006號 台北市大安區敦化南路二段97號B1 期貨總公司電話:(02)2700-2888
- Handle
- @drmarkyang
- Joined
- April 25, 2014
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.