At a glance
Subscribers
268
Views
110,471
Videos
0
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Views per subscriber
412×
Total views ÷ subscribers
Analytics tables
About
- Joined
- October 4, 2026
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
How LEGO - Topic is doing
It has 268 subscribers and 110K total views, ranking #4,459,160 by subscribers and #3,637,778 by views among tracked channels.
Key facts about LEGO - Topic
- Total videos
- 0
- Global rank by subscribers
- #4,459,160
- Global rank by views
- #3,637,778
Frequently asked questions
How many subscribers does LEGO - Topic have?
LEGO - Topic has 268 subscribers, 110,471 total views, ranking #4,459,160 among tracked channels by subscribers.
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.