아무트Amut
@아무트amut • Joined December 31, 2022
At a glance
아무트Amut ranks #2,080,565 globally for subscribers (3.53K), #1,603,428 globally for views (1.68M), 305 videos published.
Subscribers
3,530
Views
1,689,107
Videos
305
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
5.53K
Total views ÷ total videos
Views per subscriber
479×
Total views ÷ subscribers
Subs per video
12
Subscribers ÷ total videos
Analytics tables
About
안녕하세요~ 유튜버 아무트Amut입니다!😀 제가 하는 게임들은 전부 다 올리지만, 주로 로블록스를 올립니다! 그 중에서도 현재는 라이벌을 주로 올리고 있어요!😄 영상 올리는 주기는 아직 없습니다...😥 제가 올리고 싶을때 영상이 올라갈 예정입니다!😅
- Handle
- @아무트amut
- Joined
- December 31, 2022
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.