여비
@여비당 • Joined September 19, 2012
At a glance
여비 ranks #909,420 globally for subscribers (34.0K), #956,840 globally for views (7.39M), 1.29K videos published from KR.
Subscribers
34,030
Views
7,394,856
Videos
1,291
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
5.72K
Total views ÷ total videos
Views per subscriber
217×
Total views ÷ subscribers
Subs per video
26
Subscribers ÷ total videos
Analytics tables
About
[광고 문의] : [email protected] 게임 유튜버로 여러분들에게 행복을 주고 싶네요~ 방송 재밌게 봐주시고 항상 노력하는 여비가 되겠습니다!! 재밌게 보셨다면 구독! 좋아요♡ 부탁드립니다^^!! 카톡 1:1오픈톡 https://open.kakao.com/o/slFlIiFf
- Handle
- @여비당
- Joined
- September 19, 2012
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.