At a glance
ibao【愛包枕】 ranks #1,729,499 globally for subscribers (6.25K), #2,030,442 globally for views (744K), 157 videos published from TW.
Subscribers
6,250
Views
744,353
Videos
157
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
4.74K
Total views ÷ total videos
Views per subscriber
119×
Total views ÷ subscribers
Subs per video
40
Subscribers ÷ total videos
Analytics tables
About
ibao【愛包枕 】~ love your beloved bag 愛包,為包而生 細節、優雅、與眾不同 體驗愛包所帶來的優雅 為您的愛包提供專屬產品及服務 亞洲區第一精品包包防護品牌 🛍官網首購優惠+VIP全年優惠 🛍台港澳官網直購 www.ibaolovebags.com 🛍LINE ID @ibao.tw 🛍微信請搜 爱包枕ibao 🛍IG #ibaolovebags
- Handle
- @ibaolovebags
- Joined
- March 8, 2017
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.