Diogo Estima bannerDiogo Estima banner
Diogo EstimaDiogo Estima

Diogo Estima

Portugal@nte8437  •  Joined September 27, 2017

Live
Sub 37  |  View 0  |  Video 0
#5,545,260
#9,085Portugal
#8,136,089
#10,346Portugal

At a glance

Diogo Estima ranks #5,545,260 globally for subscribers (37).

Subscribers

37

Views

0

Videos

0

Charts

Subscribers, views & videos over time

Hover or tap the chart to see values

Subscribers gained (weekly) · 6 mo

Views gained (weekly) · 6 mo

Engagement

Views per subscriber

Total views ÷ subscribers

Revenue estimate

Details →

View data needed for estimate.

Based on estimated $0.7–$2 CPM.

Analytics tables

About

Canal para o fun! Nick Ps4: RTN-_-Sasuke Discord: https://discord.gg/6RtcxD

Handle
@nte8437
Joined
September 27, 2017

More features coming

We're working on new analytics and tools. Stay tuned.

Frequently asked questions

How accurate are these YouTube channel analytics?

Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.

How is a channel's global and country rank calculated?

Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.

How is the revenue estimate calculated?

It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.

Can I check analytics for any YouTube channel, not just my own?

Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.

Is this YouTube channel analytics checker free?

Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.