At a glance
Noova ranks #1,300,392 globally for subscribers (14.5K), #1,733,057 globally for views (1.29M), 184 videos published.
Subscribers
14,594
Views
1,295,583
Videos
184
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
7.04K
Total views ÷ total videos
Views per subscriber
89×
Total views ÷ subscribers
Subs per video
79
Subscribers ÷ total videos
Analytics tables
About
𝑳ă𝒔𝒂ț𝒊 𝒖𝒏 𝒎𝒂𝒓𝒆 𝒍𝒊𝒌𝒆 ș𝒊 𝒔𝒖𝒃𝒔𝒄𝒓𝒊𝒃𝒆 𝒅𝒂𝒄𝒂 𝒗𝒂 𝒑𝒍𝒂𝒄𝒆 𝒄𝒐𝒏𝒕𝒆𝒏𝒕𝒖𝒍 😘😘❤️⭐ 𝑰𝑵𝑭𝑶𝑹𝑴𝑨Ț𝑰: 𝑨𝒎 19 𝒂𝒏𝒊 𝑱𝒐𝒄 𝒑𝒆 𝑰𝒑𝒂𝒅 𝒑𝒓𝒐 11 2020 𝑬𝒅𝒊𝒕𝒆𝒛 𝒄𝒖 𝑳𝒖𝒎𝒂𝑭𝒖𝒔𝒊𝒐𝒏 𝑱𝒐𝒄 4 𝒅𝒆𝒈𝒆𝒕𝒆 𝑰𝒏𝒔𝒕𝒂𝒈𝒓𝒂𝒎: adr1an___ 𝑭𝒂𝒄𝒆𝒃𝒐𝒐𝒌: 𝑨𝒍𝒆𝒙 𝑨𝒅𝒓𝒊𝒂𝒏 TikTok: …
- Handle
- @eusuntnoova
- Joined
- December 28, 2018
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.