At a glance
제주커플jeju-couple ranks #131,847 globally for subscribers (524K), #37,424 globally for views (765M), 770 videos published from KR.
Subscribers
524,000
Views
765,933,145
Videos
770
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
994K
Total views ÷ total videos
Views per subscriber
1,462×
Total views ÷ subscribers
Subs per video
681
Subscribers ÷ total videos
Analytics tables
About
제주로 시집온 미도리와 결혼생활 영상일기! 미도리 = 미짱 = 매우 한국인같은 일본여자 준짱 = 미도리를 놀리기위해 결혼한 한국남자 소랑이 = 제주커플 구독자를 사랑하여 지어진 구독자애칭 여러분의 구독과 댓글은 정말 큰 힘이 됩니다! 항상 감사해요~ 각종 문의는 이메일로 부탁드립니다. ▶ [email protected]
- Handle
- @jejucouple
- Joined
- December 7, 2018
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.