小白科技浅谈
@xiaobaitalks • Joined November 27, 2023
At a glance
小白科技浅谈 #6,680,993 globally for views (498), 7 videos published.
Subscribers
0
Views
498
Videos
7
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
71
Total views ÷ total videos
Analytics tables
About
👋 欢迎来到【小白科技浅谈】！ 这里专注于用最通俗直白、硬核有趣的手绘隐喻，为你拆解全球最新的 AI 革命、开源黑科技与未来生产力工具。 💡 我们主要聊什么： • 🤖 最新 AI 大模型实测与深度解析（DeepSeek / MiniMax / Claude 等） • 🛠️ 适合普通人的极简本地部署与算力进阶（ComfyUI / llama.cpp / 量化模型） • 🧠 认知破局与思维模型：在 AI 时代保护自己的核心竞争力与未来生存法则 让前沿科技不再晦涩难懂，带你用最低认知成本跟上时代浪潮。 🔔 欢迎点击「订阅」并开启小铃铛，第一时间掌握最新黑科技！ 商业合作 / 交流：请查看下方商务邮箱 #AI #人工智能…
- Handle
- @xiaobaitalks
- Joined
- November 27, 2023
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.