At a glance
焼おにぎりの等速巻き ranks #1,384,232 globally for subscribers (12.2K), #978,051 globally for views (6.22M), 361 videos published from JP.
Subscribers
12,224
Views
6,227,578
Videos
361
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
17.2K
Total views ÷ total videos
Views per subscriber
509×
Total views ÷ subscribers
Subs per video
34
Subscribers ÷ total videos
Analytics tables
About
週末海が荒れると気が狂う週末アングラーです😆 1年間ほぼオフショアでタイラバをしてます🎣 タイラバをこよなく愛するいわゆる病気です☺️ 瀬戸内海、日本海によく出現します! 新相棒エボシ340【辻堂加工株式会社】に スズキ6馬力⇨トーハツ9.8馬力にパワーアップしました! ボートも憧れていたダブルデッキにレベルアップしたけど激重で毎回ヒーヒー言いながらドーリーで運んでます💪
- Handle
- @yakioni
- Joined
- January 28, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.