At a glance
兵王聂二狗 ranks #4,746,569 globally for subscribers (162), #4,738,945 globally for views (18.0K), 262 videos published from HK.
Subscribers
162
Views
18,013
Videos
262
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
69
Total views ÷ total videos
Views per subscriber
111×
Total views ÷ subscribers
Subs per video
1
Subscribers ÷ total videos
Analytics tables
About
🎥✨欢迎踏入 ‘兵王聂二狗 ’的奇幻动画王国!. 在这里,每帧画面都是脑洞的狂欢,每段故事都藏着意想不到的惊喜~原创剧情搭配超燃画风,带你解锁动画世界的无限可能! 下一期想看「聂二狗的太空大作战」还是「古风江湖奇遇记」?速速订阅频道并点击小铃铛🔔,最新原创动画准时更新! 频道所有视频均获中国大陆创作者授权,严格遵守平台规定。内容故事纯属虚构,部分情节为剧情需要,未成年人请勿模仿,无不良引导。
- Handle
- @bingwangnieergou
- Joined
- May 29, 2025
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.