2hswd
@2hswd • Joined July 2, 2009
At a glance
2hswd ranks #1,051,671 globally for subscribers (23.3K), #609,644 globally for views (17.3M), 60 videos published.
Subscribers
23,334
Views
17,332,190
Videos
60
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
288K
Total views ÷ total videos
Views per subscriber
743×
Total views ÷ subscribers
Subs per video
389
Subscribers ÷ total videos
Analytics tables
About
オールドアニメ、特に1970~1980年代のアニメ好きに響く何か。 当チャンネルは広告による収益を一切受けていません。 著作権者様へ: 投稿動画について何か問題がありましたら、お手数ですが下記emailへご連絡ください。対処させて頂きます。 作品の製作に携わった、特に現場で作り上げた方々に何らかの還元がなされる事を望んでいます。 Email: 88hushpuppy_gmail.com 上記"_"を"@"に変えてください。
- Handle
- @2hswd
- Joined
- July 2, 2009
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
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Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.