At a glance
Euphoric Bear ranks #2,054,649 globally for subscribers (3.64K), #1,876,871 globally for views (1.00M), 57 videos published.
Subscribers
3,640
Views
1,002,671
Videos
57
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
17.5K
Total views ÷ total videos
Views per subscriber
275×
Total views ÷ subscribers
Subs per video
64
Subscribers ÷ total videos
Analytics tables
About
𝙷𝚒! 𝚈𝚘𝚞 𝚌𝚊𝚗 𝚌𝚊𝚕𝚕 𝚖𝚎 𝙺𝚊𝚝. ೃ♡ About me 🍰 𝙸'𝚖 𝙺𝚊𝚝. 𝙼𝚢 𝚙𝚛𝚘𝚗𝚘𝚞𝚗𝚜 𝚊𝚛𝚎 𝚜𝚑𝚎/𝚑𝚎𝚛 𝙰 𝚙𝚛𝚘𝚞𝚍 𝙱𝚃𝚂 𝚊𝚛𝚖𝚢. 𝙸 𝚕𝚒𝚔𝚎 𝚝𝚘 𝚌𝚛𝚎𝚊𝚝𝚎 𝚖𝚢 𝚘𝚠𝚗 𝚠𝚘𝚛𝚕𝚍 𝚊𝚗𝚍 𝚕𝚒𝚟𝚎 𝚝𝚑𝚎𝚛𝚎. 𝙰𝚗 𝚒𝚗𝚝𝚛𝚘𝚟𝚎𝚛𝚝 𝚠𝚑𝚘 𝚜𝚝𝚊𝚢𝚜 𝚒𝚗 𝚑𝚎𝚛 𝚛𝚘𝚘𝚖 𝚌𝚛𝚎𝚊𝚝𝚒𝚗𝚐 𝚊 𝚍𝚒𝚏𝚏…
- Handle
- @euphoricbear
- Joined
- September 8, 2020
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.