小盒子
@小盒子 • Joined May 31, 2014
At a glance
小盒子 ranks #1,195,880 globally for subscribers (17.9K), #1,162,282 globally for views (4.19M), 595 videos published from TW.
Subscribers
17,994
Views
4,195,121
Videos
595
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
7.05K
Total views ÷ total videos
Views per subscriber
233×
Total views ÷ subscribers
Subs per video
30
Subscribers ÷ total videos
Analytics tables
About
記得訂閱按讚加分享💜 開啟小鈴鐺🔔不要錯過任何一期精彩視頻～ 一在天天玩樂園✨ PLAY TOGETHER🟢 點擊上方影片攔播放與小編一探究竟有什麼吧⁉️ 請大家踴躍在下方留言區分享你們主觀及客觀的看法分享給需要的人 也讓小編看到噢❤️ ⚠️客服中心：https://instagram.com/a0928318414?r=nametag
- Handle
- @小盒子
- Joined
- May 31, 2014
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.