At a glance
愛迪生玩遊戲 ranks #354,817 globally for subscribers (156K), #321,773 globally for views (53.9M), 738 videos published from CA.
Subscribers
156,078
Views
53,967,054
Videos
738
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
73.1K
Total views ÷ total videos
Views per subscriber
346×
Total views ÷ subscribers
Subs per video
211
Subscribers ÷ total videos
Analytics tables
About
中老年生活&遊戲分享~ 不以物喜不以己悲 有事請聯繫: [email protected] Bilibili主頁:https://space.bilibili.com/629707370 Discord:https://discord.com/invite/fcNJUtV6kE 微博:https://weibo.com/edisonwanyouxi 喜欢的朋友請點讚和訂閱我的頻道~
- Handle
- @edisonnnn
- Joined
- July 12, 2020
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.