Good Cookiene
@goodcookiene636 • Joined July 4, 2019
At a glance
Good Cookiene ranks #7,300,043 globally for subscribers (8), #6,214,508 globally for views (1.30K), 6 videos published.
Subscribers
8
Views
1,301
Videos
6
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
217
Total views ÷ total videos
Views per subscriber
163×
Total views ÷ subscribers
Subs per video
1
Subscribers ÷ total videos
Analytics tables
About
명품 수제쿠키전문점 착한쿠키네를 알리고, 착한쿠키네가 사용하는 유기농 재료, 반죽, 쿠키 제작 과저을 소개하고, 각종 수제쿠키를 보여드려요. 착한쿠키네가 만드는 결혼답례쿠키,생일답례쿠키,조문답례쿠키,행사답례쿠키,시보해제쿠키 등 각종 수제쿠키답례품 등에 대한 정보를 제공해요.
- Handle
- @goodcookiene636
- Joined
- July 4, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.