똑독-똑똑한강아지
@똑독-똑똑한강아지 • Joined January 10, 2019
At a glance
똑독-똑똑한강아지 ranks #7,399,389 globally for subscribers (4), #6,025,928 globally for views (731), 2 videos published from KR.
Subscribers
4
Views
731
Videos
2
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
366
Total views ÷ total videos
Views per subscriber
183×
Total views ÷ subscribers
Subs per video
2
Subscribers ÷ total videos
Analytics tables
About
올바른애견교육,애견용품리뷰,애견생활훈육과 애견관련정보를 시원하게 해결해드리겠습니다 애견학교 애견행동교정 애견호텔 애견질병 애견용품 대소변훈련 짖음문제 산책예절 애견목욕 애견미용 애견훈련소 유기견없는나라 애견관련정보 및 생생한리뷰로 후려치는 컨텐츠로 30년노하우 정통훈련사가 전달해드립니다.
- Handle
- @똑독-똑똑한강아지
- Joined
- January 10, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.