At a glance
Wise Chicken ranks #1,117,559 globally for subscribers (20.6K), #819,401 globally for views (9.49M), 59 videos published from US.
Subscribers
20,600
Views
9,498,876
Videos
59
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
160K
Total views ÷ total videos
Views per subscriber
461×
Total views ÷ subscribers
Subs per video
349
Subscribers ÷ total videos
Analytics tables
About
🎉 **𝑰 𝒎𝒂𝒌𝒆 𝑮𝒂𝒄𝒉𝒂 𝒗𝒊𝒅𝒆𝒐𝒔! 🗿 𝑻𝒉𝒊𝒔 𝑪𝒉𝒂𝒏𝒏𝒆𝒍 𝑼𝒑𝒍𝒐𝒂𝒅𝒔: 𝑨𝒏𝒊𝒎𝒆 𝑮𝒂𝒄𝒉𝒂 𝑹𝒆𝒂𝒄𝒕𝒊𝒐𝒏𝒔 𝒂𝒏𝒅 𝒐𝒕𝒉𝒆𝒓 𝒆𝒙𝒄𝒊𝒕𝒊𝒏𝒈 𝒂𝒏𝒊𝒎𝒆 𝒄𝒐𝒏𝒕𝒆𝒏𝒕 🌟 - 𝑴𝒚 𝒇𝒂𝒗𝒐𝒖𝒓𝒊𝒕𝒆 𝒂𝒏𝒊𝒎𝒆: 1️⃣ 𝑴𝒂𝒕𝒐 𝒔𝒆𝒊𝒉𝒆𝒊 𝒏𝒐 𝒔𝒍𝒂𝒗𝒆✨ 2️⃣ 𝑶𝒏𝒆 𝑷𝒖𝒏𝒄𝒉 𝒎𝒂𝒏💥 3️⃣ 𝑱𝒖𝒋𝒖𝒕𝒔�…
- Handle
- @wisechicken5
- Joined
- April 7, 2024
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.