At a glance
ベビ太郎 ranks #1,486,757 globally for subscribers (10.1K), #1,150,852 globally for views (4.16M), 213 videos published from JP.
Subscribers
10,100
Views
4,162,161
Videos
213
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
19.5K
Total views ÷ total videos
Views per subscriber
412×
Total views ÷ subscribers
Subs per video
47
Subscribers ÷ total videos
Analytics tables
About
ベビ太郎では、バンライフ(車中生活)をする為に100系ハイエースをメルカリで185,000円で購入しました! そのハイエースをDIYする過程であったり、日本全国を旅しながら配信していければと考えております。 ぜひチャンネル登録と通知ボタンを押して、動画をお楽しみください^_^ 2019-01-08 チャンネル開設 2020-04-27 チャンネル登録者数 1000人突破
- Handle
- @babytaroudesu
- Joined
- January 8, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.