長谷川幸洋のNEWSチャンネル
@長谷川幸洋の • Joined February 14, 2020
At a glance
長谷川幸洋のNEWSチャンネル ranks #203,676 globally for subscribers (318K), #167,118 globally for views (140M), 1.43K videos published from JP.
Subscribers
318,906
Views
140,093,446
Videos
1,431
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
97.8K
Total views ÷ total videos
Views per subscriber
439×
Total views ÷ subscribers
Subs per video
223
Subscribers ÷ total videos
Analytics tables
About
〈番組概要〉 政治、経済、国際関係など時々の重要ニュースを取り上げ「リアリズム」の視点で、次の展開を大胆に予測します。 〈主な出演者〉 MC：長谷川幸洋（ジャーナリスト） ゲスト（随時） 〈番組コンセプト〉 「ここでしか言えない話」を思う存分、語ります。
- Handle
- @長谷川幸洋の
- Joined
- February 14, 2020
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.