At a glance
RuS_AkuLA ranks #150,083 globally for subscribers (454K), #145,570 globally for views (167M), 1.70K videos published from RU.
Subscribers
454,340
Views
167,541,548
Videos
1,701
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
98.4K
Total views ÷ total videos
Views per subscriber
369×
Total views ÷ subscribers
Subs per video
267
Subscribers ÷ total videos
Analytics tables
About
5f63e390-ec0a-45ae-99e4-9b90a034fdc8 Не подписался значит пукнул 😂пук пук 🔥с вами RuS_AkuLA мне 34 зовут Евгений , играю в 3 пальца iphone 17 pro max Наушники MoonDrop Blessing 3 Вентилятор 12 ВВ кто хочет дарить uc 5346974111 мой айди
- Handle
- @rus_akula
- Joined
- July 17, 2023
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
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Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.