Zexxy10K
@zexxy10k • Joined August 12, 2024
At a glance
Zexxy10K ranks #1,557,472 globally for subscribers (9.04K), #1,427,040 globally for views (2.38M), 86 videos published from IN.
Subscribers
9,048
Views
2,388,880
Videos
86
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
27.7K
Total views ÷ total videos
Views per subscriber
264×
Total views ÷ subscribers
Subs per video
105
Subscribers ÷ total videos
Analytics tables
About
𝙨𝙤! 𝙝𝙚𝙮 𝙜𝙪𝙮𝙨🙋♂️ 👋 𝙆𝙖𝙞𝙨𝙖 𝙝𝙤 𝙖𝙖𝙥 𝙡𝙤𝙜 💗 𝙄 𝙣𝙚𝙚𝙙 𝙖 𝙝𝙚𝙡𝙥 🙂𝙥𝙡𝙯 𝙨𝙪𝙥𝙥𝙤𝙧𝙩 𝙤𝙪𝙧 💁♂️💗𝙔𝙏 𝙥𝙖𝙜𝙚 𝙖𝙣𝙙 𝙙𝙤𝙣'𝙩 𝙛𝙤𝙧𝙜𝙚𝙩 𝙖𝙗𝙤𝙪𝙩 𝙨𝙪𝙗𝙨𝙘𝙧𝙞𝙗𝙚 𝙩𝙝𝙚 𝙤𝙪𝙧 𝙔𝙏 𝙘𝙝𝙖𝙣𝙣𝙚𝙡 👍💗
- Handle
- @zexxy10k
- Joined
- August 12, 2024
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.