諧星們
@諧星們 • Joined January 10, 2021
At a glance
諧星們 ranks #613,446 globally for subscribers (66.5K), #570,836 globally for views (19.5M), 326 videos published from TW.
Subscribers
66,500
Views
19,587,361
Videos
326
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
60.0K
Total views ÷ total videos
Views per subscriber
295×
Total views ÷ subscribers
Subs per video
204
Subscribers ÷ total videos
Analytics tables
About
此為喜劇人中文官方頻道! 往後會定時為大家制作多樣的有趣影片,希望給大家帶來歡樂! 請大家多多支持!! 有興趣也請到我們的主頁訪問喔,有什麼想看的主題也可以留言給我們 我們會收集大家的建議特別創作大家有興趣的視頻 歡迎任何商業合作: [email protected] 中國小伙伴可以在B站搜尋 " 喜剧人Official "
- Handle
- @諧星們
- Joined
- January 10, 2021
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.