幼稚緣 【最新寶可夢資訊】
@childishpokemon • Joined December 29, 2020
At a glance
幼稚緣 【最新寶可夢資訊】 ranks #1,573,272 globally for subscribers (8.70K), #1,794,706 globally for views (1.16M), 89 videos published from TW.
Subscribers
8,703
Views
1,167,777
Videos
89
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
13.1K
Total views ÷ total videos
Views per subscriber
134×
Total views ÷ subscribers
Subs per video
98
Subscribers ÷ total videos
Analytics tables
About
歡迎來到我的頻道！幼稚緣會分享最新的寶可夢資訊，包括遊戲更新、攻略教學和新版本解析。記得訂閱並開啟通知，隨時掌握最新寶可夢動態！ 合作邀約請聯絡郵箱：[email protected] 立即加入我們，成為最強的寶可夢訓練家吧！
- Handle
- @childishpokemon
- Joined
- December 29, 2020
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.