打野哥
@打野哥-b5f • Joined June 4, 2012
At a glance
打野哥 ranks #493,450 globally for subscribers (97.1K), #302,891 globally for views (59.1M), 4.15K videos published from TW.
Subscribers
97,100
Views
59,120,577
Videos
4,154
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
14.2K
Total views ÷ total videos
Views per subscriber
609×
Total views ÷ subscribers
Subs per video
23
Subscribers ÷ total videos
Analytics tables
About
EJ Gamers 實況團隊合作信箱：[email protected]】［任何工作邀約都請寄信到信箱］ 傳說對決為主頻道 傳說對決最高ss第3 城市賽冠軍2次 亞軍無數次 台灣區S2季軍 新加坡邀請賽亞軍 工商請私訊粉絲頁(打野哥) 目前直播在YT 晚上九點後 歐富寶贊助 https://reurl.cc/Xy3OR
- Handle
- @打野哥-b5f
- Joined
- June 4, 2012
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.