At a glance
김종갑의 경제부동산 ranks #143,425 globally for subscribers (477K), #162,767 globally for views (144M), 2.52K videos published from KR.
Subscribers
477,402
Views
144,717,279
Videos
2,528
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
57.2K
Total views ÷ total videos
Views per subscriber
303×
Total views ÷ subscribers
Subs per video
189
Subscribers ÷ total videos
Analytics tables
About
◈ 김종갑의 경제부동산 ☎유료상담☎ 010-2626-6276 ★ 부동산종합자산관리 ★ 투자분석 개인상담 매수, 매도시점, 투자분석, 지역분석, 전망 등 궁금한 점은 위 전화번호로 문의 부탁드립니다! ※김종갑의 경제부동산 채널 공지사항※ 강의 이용의 손실, 피해를 보거나 욕설, 비난 등 악플을 게재한 책임은 이용자에게 있습니다.
- Handle
- @drapt99
- Joined
- February 7, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.