かいのすけ 歴史
@kainosuke-rekishi • Joined April 20, 2020
At a glance
かいのすけ 歴史 ranks #991,493 globally for subscribers (26.5K), #877,908 globally for views (8.04M), 132 videos published from JP.
Subscribers
26,500
Views
8,049,636
Videos
132
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
60.9K
Total views ÷ total videos
Views per subscriber
304×
Total views ÷ subscribers
Subs per video
201
Subscribers ÷ total videos
Analytics tables
About
ご連絡はこちら [email protected] 歴史にまつわるあちこちの史跡を訪問します。 「城好き」「歴史好き」な方が増えてくれるといいです。このチャンネルを見て城に行きたい！と思ってくだされば本当にありがたいです。コメントなど、お気軽にご連絡ください。
- Handle
- @kainosuke-rekishi
- Joined
- April 20, 2020
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.