At a glance
宅物獵人 Kushi Mochi ranks #3,243,433 globally for subscribers (760), #2,852,548 globally for views (212K), 126 videos published from TW.
Subscribers
760
Views
212,628
Videos
126
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
1.68K
Total views ÷ total videos
Views per subscriber
280×
Total views ÷ subscribers
Subs per video
6
Subscribers ÷ total videos
Analytics tables
About
宅物獵人帶領你一同去探索那個讓錢變不見的深淵~ 有空歡迎來逛逛我們的蝦皮賣場: https://reurl.cc/dWWWn8 (訂閱有神秘折扣喔) 想要與我們合作的話,可以透過下面這些管道喔~ FB:https://reurl.cc/ER852A Email:[email protected] 郵箱:114台北市內湖區康寧路三段22之1號 內湖康寧郵局28號郵箱
- Handle
- @kushimochi3308
- Joined
- March 14, 2021
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.