Аналитика Ошибок
@dotaanalytics • Joined February 26, 2017
At a glance
Аналитика Ошибок ranks #97,938 globally for subscribers (724K), #68,563 globally for views (413M), 2.47K videos published.
Subscribers
724,330
Views
413,867,343
Videos
2,474
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
167K
Total views ÷ total videos
Views per subscriber
571×
Total views ÷ subscribers
Subs per video
293
Subscribers ÷ total videos
Analytics tables
About
№ 5062176116 Аналитика ошибок из мира Дота 2, подробные гайды Дота 2, детальный обзор, обучение игры в Дота 2 AVedwbSobWxe
- Handle
- @dotaanalytics
- Joined
- February 26, 2017
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.