At a glance
星島溫哥華 ranks #2,553,680 globally for subscribers (1.82K), #2,103,598 globally for views (696K), 867 videos published from CA.
Subscribers
1,820
Views
696,297
Videos
867
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
803
Total views ÷ total videos
Views per subscriber
383×
Total views ÷ subscribers
Subs per video
2
Subscribers ÷ total videos
Analytics tables
About
星島溫哥華自1983年服務大溫地區華人社群,提供溫哥華、卑詩省及加拿大本地新聞、社區資訊、生活專題及本地活動內容。 本頻道聚焦溫哥華及卑詩本地消息,涵蓋大溫、列治文、本拿比、素里等地新聞,包括時事、治安、交通、房屋、教育、移民、公共政策及社區議題。 除本地新聞外,頻道亦會分享大溫生活及社區內容,包括文化活動、人物故事、飲食消費、節慶活動、娛樂資訊及本地生活話題。
- Handle
- @singtaovancouver7429
- Joined
- September 23, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.