At a glance
히트다히트 ranks #1,278,327 globally for subscribers (15.2K), #1,071,991 globally for views (5.10M), 313 videos published from KR.
Subscribers
15,238
Views
5,100,358
Videos
313
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
16.2K
Total views ÷ total videos
Views per subscriber
335×
Total views ÷ subscribers
Subs per video
49
Subscribers ÷ total videos
Analytics tables
About
FTV, FSTV에서 방송활동을 하던 이준열프로가 유튜브를 통해 최대한 빠른시간내에 집어와 마릿수 획득의 스킬을 보여줘서 입문자분들께 낚시테크닉과 요령을 직접 설명하는 프로그램 입니다 촬영관련문의는 인스타 카카오톡에서 DM주시기 바랍니다 인스타그램 : leejunyel 이메일 : [email protected] 카카오톡 junlee13
- Handle
- @lee-pro
- Joined
- September 16, 2019
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.