At a glance
O B A N A I 蛇 ranks #1,164,424 globally for subscribers (19.1K), #924,430 globally for views (7.36M), 61 videos published from CA.
Subscribers
19,100
Views
7,369,789
Videos
61
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
120K
Total views ÷ total videos
Views per subscriber
386×
Total views ÷ subscribers
Subs per video
313
Subscribers ÷ total videos
Analytics tables
About
𝒰𝓂𝓂𝓂 𝒶𝓃𝒾𝓂𝑒 𝑒𝒹𝒾𝓉𝓏 𝒜𝓃𝒹 𝓂𝑜𝓇𝑒 𝒾 𝑔𝓊𝑒𝓈𝓈 𝑒,𝑒 𝐈𝐧𝐟𝐨 𝐚𝐛𝐨𝐮𝐭 𝐦𝐞: ►𝐍𝐚𝐦𝐞: 𝐌𝐢𝐤𝐞 ►𝐎𝐥𝐝: 𝟐𝟎 ►𝐁𝐨𝐫𝐧: 𝟏𝟒 𝐉𝐮𝐧𝐞 𝐅𝐚𝐯𝐨𝐫𝐢𝐭𝐞 𝐀𝐧𝐢𝐦𝐞: ❖𝐍𝐚𝐫𝐮𝐭𝐨 𝐒𝐡𝐢𝐩𝐩𝐮𝐝𝐞𝐧 ❖𝐊𝐢𝐦𝐞𝐭𝐬𝐮 𝐍𝐨 𝐘𝐚𝐢𝐛𝐚 ❖𝐁𝐥𝐞𝐚𝐜𝐡 ❖𝐎𝐰𝐚𝐫𝐢 𝐧𝐨 𝐬𝐞𝐫𝐚𝐩𝐡 ❖𝐉𝐮𝐣𝐮𝐭𝐬𝐮 𝐤𝐚𝐢𝐬𝐞…
- Handle
- @obanai_205
- Joined
- September 13, 2018
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.