UmaAndZi
@umaandzi • Joined June 10, 2022
At a glance
UmaAndZi ranks #5,037,565 globally for subscribers (120), #4,114,510 globally for views (51.5K), 27 videos published from TW.
Subscribers
120
Views
51,566
Videos
27
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
1.91K
Total views ÷ total videos
Views per subscriber
430×
Total views ÷ subscribers
Subs per video
4
Subscribers ÷ total videos
Analytics tables
About
大家好~這裡有三隻貓貓，個性都截然不同 (๑ↀᆺↀ๑)✧ Uma - 傲驕虎斑,貓界美男,身上永遠都是香的 Zi - 愛說話整天邀巴剎的三花小女生, Starbon - 屁孩一隻,很賓的賓士 這裡不僅有貓咪和音樂,還有一些有趣的影片,希望有陪伴到你 ヽ༼◕_◕༽ﾉ 如果你喜歡,也請給我一些鼓勵,讓我有持續經營的動力 💛
- Handle
- @umaandzi
- Joined
- June 10, 2022
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.