At a glance
JEEDOL POWER 3D ranks #1,372,145 globally for subscribers (12.8K), #1,131,434 globally for views (4.47M), 63 videos published from KR.
Subscribers
12,806
Views
4,474,739
Videos
63
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
71.0K
Total views ÷ total videos
Views per subscriber
349×
Total views ÷ subscribers
Subs per video
203
Subscribers ÷ total videos
Analytics tables
About
안녕하세요? 3D 장난감 아티스트, 지돌파워(Jee-dol Power)입니다. 라이노(Rhinoceros)로 3D 모델링하고, 3D 프린터로 파트들을 출력하여 조립도 합니다. 세상에 없는 장난감을 제가 만든답니다. 감사합니다. 채널이름 : Jee-dol Power 3D, @primejee) 채널오픈 : 2022년 4월 18일
- Handle
- @primejee
- Joined
- March 22, 2022
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.