At a glance
独身貴族ワイン ranks #5,364,338 globally for subscribers (79), #5,691,598 globally for views (3.57K), 20 videos published from JP.
Subscribers
79
Views
3,572
Videos
20
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
179
Total views ÷ total videos
Views per subscriber
45×
Total views ÷ subscribers
Subs per video
4
Subscribers ÷ total videos
Analytics tables
About
一人の夜に、缶ワインを。 仕事終わり、誰にも気を使わず、好きな時間にワインを楽しむ。 そんな“独身貴族”のための缶ワインチャンネルです。 🍷 ワイン初心者でも楽しめる缶ワインレビュー 🍽 おつまみとの最強ペアリング紹介 🏕 アウトドア・コンビニ・自宅、どこでも気軽に飲めるワイン提案 「高級ワインはまだ早い」「詳しくなくても飲みたい」 そんなあなたに向けて、月1更新で動画を発信しています。
- Handle
- @dokushinkizoku_wine
- Joined
- August 2, 2024
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.