At a glance
크리스탈의 경제공부 ranks #737,737 globally for subscribers (47.2K), #1,279,674 globally for views (3.08M), 139 videos published from KR.
Subscribers
47,200
Views
3,088,400
Videos
139
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
22.2K
Total views ÷ total videos
Views per subscriber
65×
Total views ÷ subscribers
Subs per video
340
Subscribers ÷ total videos
Analytics tables
About
투자로 연결하는 경제공부를 지향하는 경제공부코치 '크리스탈' 입니다. 📔『투자하려면 경제신문』 베스트셀러 저자 📰국내최초 경제신문스크랩 코치 📰경제신문스크랩 습관 만들기 '경신스 챌린지' 리더 ※크리스탈TV에 언급되는 종목들은 분석 자료일 뿐 절대로 추천주가 아닙니다. 따라서 모든 투자 판단과 책임은 각자에게 있습니다.
- Handle
- @crystal_economy
- Joined
- January 10, 2017
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.