At a glance
傲爸食好西 ranks #4,119,182 globally for subscribers (245), #3,526,608 globally for views (77.0K), 70 videos published.
Subscribers
245
Views
77,025
Videos
70
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
1.1K
Total views ÷ total videos
Views per subscriber
314×
Total views ÷ subscribers
Subs per video
4
Subscribers ÷ total videos
Analytics tables
About
大家好,我係傲爸👶🏻 喺呢個Channel,主要會做一D 有關食評嘅影片,希望跟同樣鐘意食野嘅觀眾,一齊討論,多D 交流。🫱🏻🫲🏼 如果你鐘意睇我嘅影片,可以like 👍🏻我嘅片,訂閱我嘅Channel同留言俾我,記得㩒埋個鐘仔🔔,有新片嘅時候大家就會睇到了。 純正香港製作,廣東話係我母語🇭🇰❤️💪🏻 如想合作,可以以下方式聯絡 Email : [email protected] WhatsApp : 60299526
- Handle
- @wind4leehk
- Joined
- July 7, 2025
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.