At a glance
CIEN ranks #1,227,900 globally for subscribers (16.4K), #1,014,582 globally for views (5.71M), 278 videos published from KR.
Subscribers
16,460
Views
5,714,726
Videos
278
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
20.5K
Total views ÷ total videos
Views per subscriber
347×
Total views ÷ subscribers
Subs per video
59
Subscribers ÷ total videos
Analytics tables
About
▶ 디아블로4 생방 / 플레이 영상 ▶ 놓치면 아쉬운 리뷰/정보/꿀팁/플레이 영상이 업데이트 됩니다 ▶ 종겜 + 게임뉴스까지! 유튜브 구독과 영상 댓글 + 좋아요는 영상 제작과 방송에 큰 힘이 됩니다 :) 모든 문의 :: [email protected] Kakaotalk ID : xoxoonight 넷이즈 유다오 :: [email protected]
- Handle
- @_cien
- Joined
- June 26, 2017
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.