At a glance
川崎市動物愛護センター ranks #3,141,329 globally for subscribers (847), #2,784,255 globally for views (227K), 191 videos published from JP.
Subscribers
847
Views
227,771
Videos
191
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
1.19K
Total views ÷ total videos
Views per subscriber
269×
Total views ÷ subscribers
Subs per video
4
Subscribers ÷ total videos
Analytics tables
About
神奈川県川崎市の動物愛護センターANIMAMALLかわさきの公式チャンネルです。 家族募集中の動物たちの紹介がメイン投稿です。 ✨️動画の投稿は毎週木曜日✨️ ※毎月第三日曜日はセンター譲渡会開催のため、その週には【譲渡会参加動物の紹介】動画を投稿します。 ぜひ、動画にグッドボタンやコメントで応援をお願いします🙌 みなさんのいいねやシェアが動物の良縁に繋がります🐱🐶
- Handle
- @animamallkawasaki
- Joined
- August 29, 2023
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.