At a glance
ClimbTourTV_클라임투어티비 ranks #455,544 globally for subscribers (109K), #101,216 globally for views (263M), 332 videos published from KR.
Subscribers
109,688
Views
263,893,428
Videos
332
Charts
Subscribers, views & videos over time
Subscribers gained (weekly) · 6 mo
Views gained (weekly) · 6 mo
Engagement
Avg. views per video
794K
Total views ÷ total videos
Views per subscriber
2,406×
Total views ÷ subscribers
Subs per video
330
Subscribers ÷ total videos
Analytics tables
About
클라이밍 종합 채널 1.암장투어 나만 알기 아까운 모든 클라이밍장을 소개합니다. 2.클라이밍 자세 클라이밍에 사용되는 자세를 쉽게 배울 수 있도록 도와줍니다 3.트레이닝 클라이밍에 적합한 트레이닝법과 실제 트레이닝을 통한 변화과정을 소개합니다 4.장비 트레이닝도구, 암벽화 등 클라이밍 시 쓰이는 도구들을 리뷰합니다
- Handle
- @클라임투어티비
- Joined
- November 27, 2018
More features coming
We're working on new analytics and tools. Stay tuned.
More features coming
We're working on new analytics and tools. Stay tuned.
Frequently asked questions
How accurate are these YouTube channel analytics?
Subscriber, view, and video counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what a channel owner sees privately in YouTube Studio.
How is a channel's global and country rank calculated?
Rank compares this channel's subscriber count and view count against every other channel Socialcounts.org tracks, both worldwide and within its home country.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view counts — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Can I check analytics for any YouTube channel, not just my own?
Yes — search any public YouTube channel by name, handle, or channel URL. No login is required to see the basics.
Is this YouTube channel analytics checker free?
Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.