15:23Long-form

ASSASSINO DE ALUGUEL TEM AJUDA DE UM UNICÓRNIO AZUL (PARTE 01)

BrazilPublished April 14, 2022

Views 0  |  Likes 12.5K  |  Comments 185
Views#2,553,816Global
Views#25,138Brazil

Channel

SOLUCIONANDO FILMESSOLUCIONANDO FILMES
1.18M subs1.31K videosMar 2021

At a glance

Views

0

Likes

12,519

Comments

185

Performance vs. channel

Outlier score

Engagement rate

Revenue estimate

Details →

View data needed for estimate.

Based on estimated $0.7–$2 CPM.

About

SERIE: FELIZ (2017) NETFLIX Um ex-policial bêbado que virou matador acha que enlouqueceu quando um unicórnio que só ele vê lhe pede ajuda. A missão é resgatar uma garota sequestrada por Papai Noel. Deixa o LIKE! pra FORTALECER! INSTAGRAM: @solucionandofilmes EDIÇÃO E NARRAÇÃO: CHICO

Published
April 14, 2022
Made for kids
No

More features coming

We're working on new analytics and tools. Stay tuned.

Frequently asked questions

How accurate are these YouTube video analytics?

View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.

What is the outlier score?

How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.

What is engagement rate and how is it calculated?

Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.

How is the revenue estimate calculated?

It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.

Is this YouTube video analytics checker free?

Yes. You get 10 free channel and video analytics lookups per rolling hour without an account — logging in, which is also free, removes that limit entirely.