I'M LEAVING THIS FAMILY... #shorts
Published January 29, 2025
At a glance
Views
497,426
Likes
20,723
Comments
85
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
- Published
- January 29, 2025
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How I'M LEAVING THIS FAMILY... #shorts is doing
It has 497K views in total. It ranks #7,047,206 among tracked YouTube videos by views.
Key facts about I'M LEAVING THIS FAMILY... #shorts
- Total views
- 497K
- Total likes
- 20.7K
- Total comments
- 85
- Published
- January 29, 2025
- Global rank by views
- #7,047,206
Frequently asked questions
How many views does I'M LEAVING THIS FAMILY... #shorts have?
I'M LEAVING THIS FAMILY... #shorts has 497,426 views, 20,723 likes and 85 comments, ranking #7,047,206 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.