이빨에 낀 고통...;;;
Published August 9, 2023
At a glance
Views
380,990
Likes
11,957
Comments
209
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
원본: https://youtu.be/N7Pp5je0C_8 #공감 #shorts 이에 뭐가 꼈을땐 이쑤시개 말고 치실을 씁시다.. uncomfortable teeth animation
- Published
- August 9, 2023
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How 이빨에 낀 고통...;;; is doing
It has 380K views in total. It ranks #7,821,814 among tracked YouTube videos by views.
Key facts about 이빨에 낀 고통...;;;
- Total views
- 380K
- Total likes
- 11.9K
- Total comments
- 209
- Published
- August 9, 2023
- Global rank by views
- #7,821,814
Frequently asked questions
How many views does 이빨에 낀 고통...;;; have?
이빨에 낀 고통...;;; has 380,990 views, 11,957 likes and 209 comments, ranking #7,821,814 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.