[그로봇 : 귀신 잡는 로봇] 예고편
Published October 25, 2021
At a glance
Views
1,486,059
Likes
16,224
Comments
1,384
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
귀신 잡는 로봇, 그로봇과 함께 승찬이가 돌아왔다! 10월 27일 수요일 6시 첫 방송!
- Published
- October 25, 2021
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How [그로봇 : 귀신 잡는 로봇] 예고편 is doing
It has 1.48M views in total. It ranks #3,859,322 among tracked YouTube videos by views.
Key facts about [그로봇 : 귀신 잡는 로봇] 예고편
- Total views
- 1.48M
- Total likes
- 16.2K
- Total comments
- 1.38K
- Published
- October 25, 2021
- Global rank by views
- #3,859,322
Frequently asked questions
How many views does [그로봇 : 귀신 잡는 로봇] 예고편 have?
[그로봇 : 귀신 잡는 로봇] 예고편 has 1,486,059 views, 16,224 likes and 1,384 comments, ranking #3,859,322 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.