[ASMR] FIDGET TOYS! QUALE VI PIACE DI PIÙ?
Published June 28, 2024
At a glance
Views
302,579
Likes
6,339
Comments
50
Performance vs. channel
All-time outlier score
Engagement rate
More features coming
We're working on new analytics and tools. Stay tuned.
About
- Published
- June 28, 2024
- Made for kids
- No
More features coming
We're working on new analytics and tools. Stay tuned.
How [ASMR] FIDGET TOYS! QUALE VI PIACE DI PIÙ? is doing
It has 302K views in total. It ranks #8,533,984 among tracked YouTube videos by views.
Key facts about [ASMR] FIDGET TOYS! QUALE VI PIACE DI PIÙ?
- Total views
- 302K
- Total likes
- 6.33K
- Total comments
- 50
- Published
- June 28, 2024
- Global rank by views
- #8,533,984
Frequently asked questions
How many views does [ASMR] FIDGET TOYS! QUALE VI PIACE DI PIÙ? have?
[ASMR] FIDGET TOYS! QUALE VI PIACE DI PIÙ? has 302,579 views, 6,339 likes and 50 comments, ranking #8,533,984 among tracked YouTube videos by views.
How accurate are these YouTube video analytics?
View, like, and comment counts come from YouTube's public API and refresh regularly. Growth and revenue figures are estimates built from tracked historical data, so they can differ slightly from what the creator sees privately in YouTube Studio.
What is the outlier score?
How this video's views compare to the channel's usual Shorts or long-form video. A 2x score means double the usual views for that channel, 0.5x means half.
What is engagement rate and how is it calculated?
Likes and comments per view, compared to this channel's typical engagement rate — shown as above or below what's usual for the channel.
How is the revenue estimate calculated?
It's a rough public estimate based on a $0.7–$2.0 CPM (revenue per 1,000 views) applied to view count — not actual creator earnings, which depend on ad rates, audience geography, and monetization settings YouTube doesn't expose publicly.
Is this YouTube video analytics checker free?
Yes. You get 10 free channel and video analytics lookups per 24 hours without an account — logging in, which is also free, removes that limit entirely.